lesson 5#7
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serg0761 wants to merge 1 commit into
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Dzhoker1
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Nov 11, 2018
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| numbers_of_company = int(input('Введите количество компаний: ')) | ||
| if numbers_of_company == 0: | ||
| print('Работникам ПВО большой привет!') |
| for i in range(numbers_of_company): | ||
| company_name = (str(input(f'Введите название компании {i + 1}:'))) | ||
| year_summ = quarter_summ = 0 | ||
| for i in range(4): |
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for i in range(1, 5):
И как итог экономим несколько тактов процессора на +1 в строке 25.
Мелочь, а приятно )))
| full_summ = 0 | ||
| company = namedtuple('company','name, years_profit') | ||
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| for i in range(numbers_of_company): |
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Если в этом цикле i, то во вложенном пишите j
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| def input_numbers(): | ||
| num = str(input('Введите шестнадцатиричное число: ')) | ||
| numbers = list(deque(num)) #т.к. по условию задачи хранить |
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Речь шла о массиве.
В Python массивов нет. Зато есть list, tuple и deque, которые можно считать массивом с дополнительным функционалом.
| print('Последовательно введите два шестнадцатиричных числа') | ||
| first_number = input_numbers() | ||
| second_number = input_numbers() | ||
| summ_numbers = make_hexadecimal(read_numbers(first_number) + |
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Не совсем в столбик. Скорее даже в строку, а не в столбик.
Но работает верно.
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