I faced this question during my oops labs, maybe you could add this t…

Q1.cpp

@@ -0,0 +1,60 @@
+#include <bits/stdc++.h>
+using namespace std;
+
+class Complex
+{   public:
+    int real;
+    int imag;
+
+    Complex()//default constructor
+    {   this->real=0;
+        this->imag=0;
+    }
+    Complex(int real, int imag)//making a complex number
+    {   this->real=real;
+        this->imag=imag;
+    }
+    Complex operator + (Complex const &b)//add 2 complex numbers
+    {   Complex c;
+        c.real=real+b.real;
+        c.imag=imag+b.imag;
+        return c;
+    }
+    Complex& operator * (Complex const &b)//multiply 2 complex numbers
+    {   int temp;
+        temp=((real * b.real)-(imag * b.imag));
+        imag=((real * b.imag)+(imag * b.real));
+        real=temp;
+        return *this;
+    }
+    operator float() const//cast into float form as per c part
+    {   float i=0;
+        float s=real/abs(real);
+        i+=abs(real); //real part will retain it's sign that is -4+2i will become -4.2
+        if(imag==0)
+        return i*s;
+
+        int digits =log10(abs(imag))+1;//incase imaginary part is negative we will ignore that like for 2-3i we will show 2.3
+        float temp=(float)(abs(imag))/(float)pow(10,digits);//incase imaginary part has zero behind it, we will ommit them like for 2+10i we will show 2.1
+        i+=temp;
+        return i*s;
+    }
+};
+
+int main()
+{   int x1,y1,x2,y2;
+    cout<<"Enter Real and Imaginary parts of the first Complex Number : ";
+    cin>>x1>>y1;
+    cout<<"\nEnter Real and Imaginary parts of the second Complex Number : ";
+    cin>>x2>>y2;
+    Complex a(x1,y1);
+    Complex b(x2,y2);
+    Complex c=a+b;
+    Complex t=a;
+    a =a* b;
+    cout<<"a.) Result for Addition = "<<c.real<<"+("<<c.imag<<")i\n";
+    cout<<"b.) Result for Multiplication = "<<a.real<<"+("<<a.imag<<")i\n";
+    float f=t;
+    cout<<"c.) Casting first Complex Number to a float variable = "<<t<<"\n";
+    return 0;
+}