Hi,
Brilliant work your article is really compréhensive and you made everything so clear.
i'm working on a subject and i'm coding CPT in python.
subject describtion :
my problem is based on the past for instance this is my past A-->B
I want to know the out come for this past.
so i look at my tree and i search for all sequences with the same past and see the its outcome .
example: A-->B-->C so for this case C is the outcome for this past (that means C+=1) and i do this for the whole tree
so i can suggest the outcome for the past A-->B .
until now i can do this with CPT and i want to improve it and go to CPT+ using FSC.
I followed your steps i calculate the frequency of every subsequence and i fixed a minsub
questions:
My first question:
How to fix this minsub ?
second question FSC:
For this this question i'll give an example first
ex:we have this path A-->B-->C-->D and we know that the B-->C is frequent so i replace B-->C with X : A-->X-->D.
so now when i want to calculate the outcome for my past for example A-->B
the subsequence A-->B it will not be found in this case because B is a part of X so is there away to avoid this?
I'm looking forward to your reply
Hi,
Brilliant work your article is really compréhensive and you made everything so clear.
i'm working on a subject and i'm coding CPT in python.
subject describtion :
my problem is based on the past for instance this is my past A-->B
I want to know the out come for this past.
so i look at my tree and i search for all sequences with the same past and see the its outcome .
example: A-->B-->C so for this case C is the outcome for this past (that means C+=1) and i do this for the whole tree
so i can suggest the outcome for the past A-->B .
until now i can do this with CPT and i want to improve it and go to CPT+ using FSC.
I followed your steps i calculate the frequency of every subsequence and i fixed a
minsubquestions:
My first question:
How to fix this minsub ?
second question FSC:
For this this question i'll give an example first
ex:we have this path A-->B-->C-->D and we know that the B-->C is frequent so i replace B-->C with X : A-->X-->D.
so now when i want to calculate the outcome for my past for example A-->B
the subsequence A-->B it will not be found in this case because B is a part of X so is there away to avoid this?
I'm looking forward to your reply