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Binary_Tree_ZigZag_Traversal.py
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77 lines (62 loc) · 2.09 KB
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# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def zigzagLevelOrder(self, root: Optional[TreeNode]) -> List[List[int]]:
if not root:
return []
# For Level Order Traversing, We are going to use BST
# Creating a Queue For FIFO
queue = deque([root])
# List to store result
result = []
reverse = False
while queue:
elements = []
length = len(queue)
for i in range(length):
currNode = queue.popleft()
elements.append(currNode.val)
if currNode.left:
queue.append(currNode.left)
if currNode.right:
queue.append(currNode.right)
result.append(elements if not reverse else elements[::-1])
reverse = not reverse
return result
Method 2:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def zigzagLevelOrder(self, root: Optional[TreeNode]) -> List[List[int]]:
if not root:
return []
# For Level Order Traversing, We are going to use BST
# Creating a Queue For FIFO
queue = deque([root])
# List to store result
result = []
j = 0
while queue:
elements = []
length = len(queue)
for i in range(length):
currNode = queue.popleft()
elements.append(currNode.val)
if currNode.left:
queue.append(currNode.left)
if currNode.right:
queue.append(currNode.right)
j += 1
if j % 2 == 1:
result.append(elements)
else:
result.append(elements[::-1]
return result