LAB_sql_basic_queries.sql

USE sakila;
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-- Challenges:
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-- 1 . Display all available tables in the Sakila database.
SHOW TABLES;
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-- 2. Retrieve all the data from the tables `actor`, `film` and `customer`.
SELECT * FROM actor;
SELECT * FROM film;
SELECT * FROM customer;
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-- 3. Retrieve the following columns from their respective tables:
	-- 3.1 Titles of all films from the `film` table
    SELECT title FROM film;
    
	-- 3.2 List of languages used in films, with the column aliased as `language` from the `language` table
    SELECT name AS language FROM language;
    
	-- 3.3 List of first names of all employees from the `staff` table
    SELECT first_name FROM staff LIMIT 3; -- there are only two staff on the list
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-- 4. Retrieve unique release years.
SELECT DISTINCT release_year FROM film;
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-- 5. Counting records for database insights:
	-- 5.1 Determine the number of stores that the company has.
    SELECT COUNT(store_id) FROM store;
    
	-- 5.2 Determine the number of employees that the company has.
    SELECT COUNT(staff_id) AS 'Total employee' FROM staff;
    
	-- 5.3 Determine how many films are available for rent and how many have been rented.
    SELECT SUM(return_date IS NOT NULL) AS Available_films , SUM(return_date IS NULL) 
    AS Not_available_films  FROM rental;
    
	-- 5.4 Determine the number of distinct last names of the actors in the database.
    SELECT COUNT(DISTINCT last_name) FROM actor;
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-- 6. Retrieve the 10 longest films.
SELECT title AS 10_longest_films FROM film
ORDER BY length DESC LIMIT 10;
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-- 7.  Use filtering techniques in order to:
	-- 7.1 Retrieve all actors with the first name "SCARLETT".
    SELECT * FROM actor WHERE first_name = "SCARLETT";
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	-- BONUS: 
	-- 7.2 Retrieve all movies that have ARMAGEDDON in their title and have a duration longer than 100 minutes. 
    SELECT * FROM film
    WHERE title LIKE '%ARMAGEDDON%' AND length>100;
	
		-- *Hint: use `LIKE` operator. [More information here.](https://www.w3schools.com/sql/sql_like.asp)*
	-- 7.3 Determine the number of films that include Behind the Scenes content
    SELECT COUNT(title) FROM film
    WHERE special_features LIKE '%Behind the Scenes%';