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main.cpp
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93 lines (81 loc) · 2.6 KB
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#include <assert.h>
#include <iostream>
#include <type_traits>
#include <variant>
#include <vector>
// 请修复这个函数的定义:10 分
template <typename T>
std::ostream& operator<<(std::ostream& os, std::vector<T> const& a) {
os << "{";
for (size_t i = 0; i < a.size(); i++) {
os << a[i];
if (i != a.size() - 1) os << ", ";
}
os << "}";
return os;
}
// 请修复这个函数的定义:10 分
template <class T1, class T2>
auto operator+(std::vector<T1> const& a, std::vector<T2> const& b) {
// 请实现列表的逐元素加法!10 分
using T0 = decltype(T1{} + T2{});
const int n = std::min(a.size(), b.size());
std::vector<T0> ret(n);
for (int i = 0; i < n; ++i) {
ret[i] = a[i] + b[i];
}
return ret;
// 例如 {1, 2} + {3, 4} = {4, 6}
}
template <class T1, class T2>
std::variant<T1, T2> operator+(std::variant<T1, T2> const& a,
std::variant<T1, T2> const& b) {
// 请实现自动匹配容器中具体类型的加法!10 分
return std::visit(
[&](const auto& t1, const auto& t2) -> std::variant<T1, T2> {
return t1 + t2;
},
a, b);
}
template <class T1, class T2, class T>
std::variant<T1, T2> operator+(std::variant<T1, T2> const& a, const T& b) {
if constexpr (std::is_same_v<T1, T> || std::is_same_v<T2, T>) {
// 请实现自动匹配容器中具体类型的加法!10 分
std::variant<T1, T2> bb = b;
return a + bb;
} else {
assert(false);
}
}
template <class T1, class T2, class T>
std::variant<T1, T2> operator+(const T& a, std::variant<T1, T2> const& b) {
if constexpr (std::is_same_v<T1, T> || std::is_same_v<T2, T>) {
// 请实现自动匹配容器中具体类型的加法!10 分
std::variant<T1, T2> aa = a;
return aa + b;
} else {
assert(false);
}
}
template <class T1, class T2>
std::ostream& operator<<(std::ostream& os, std::variant<T1, T2> const& a) {
// 请实现自动匹配容器中具体类型的打印!10 分
return std::visit([&](const auto& t) -> std::ostream& { return os << t; }, a);
}
int main() {
std::vector<int> a = {1, 4, 2, 8, 5, 7};
std::cout << a << std::endl;
std::vector<double> b = {3.14, 2.718, 0.618};
std::cout << b << std::endl;
auto c = a + b;
// 应该输出 1
std::cout << std::is_same_v<decltype(c), std::vector<double>> << std::endl;
// 应该输出 {4.14, 6.718, 2.618}
std::cout << c << std::endl;
std::variant<std::vector<int>, std::vector<double>> d = c;
std::variant<std::vector<int>, std::vector<double>> e = a;
d = d + c + e;
// 应该输出 {9.28, 17.436, 7.236}
std::cout << d << std::endl;
return 0;
}