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UniquePaths.java
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36 lines (34 loc) · 1.12 KB
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package recursion_and_dynamic_programming;
/**
* @Author: Wenhang Chen
* @Description:一个机器人位于一个 m x n 网格的左上角 (起始点在下图中标记为“Start” )。
* 机器人每次只能向下或者向右移动一步。机器人试图达到网格的右下角(在下图中标记为“Finish”)。
* 问总共有多少条不同的路径?
* @Date: Created in 10:12 11/26/2019
* @Modified by:
*/
public class UniquePaths {
public int uniquePaths(int m, int n) {
// dp[i]表示起点到当前格子有多少种走法
int[][] dp = new int[m][n];
// 初始化
int i = 0, j = 0;
for (i = 0; i < m; i++) {
dp[i][0] = 1;
}
for (j = 0; j < n; j++) {
dp[0][j] = 1;
}
// 开始dp
for (i = 1; i < m; i++) {
for (j = 1; j < n; j++) {
dp[i][j] = dp[i - 1][j] + dp[i][j - 1];
}
}
return dp[m - 1][n - 1];
}
public static void main(String[] args) {
UniquePaths up = new UniquePaths();
System.out.println(up.uniquePaths(3, 2));
}
}