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LetterCombinations.java
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49 lines (45 loc) · 1.52 KB
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package recursion_and_dynamic_programming;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
/**
* @Author: Wenhang Chen
* @Description:给定一个仅包含数字 2-9 的字符串,返回所有它能表示的字母组合。
* 给出数字到字母的映射如下(与电话按键相同)。注意 1 不对应任何字母。
* @Date: Created in 13:06 11/18/2019
* @Modified by:
*/
public class LetterCombinations {
// 灵活使用HashMap
Map<String, String> phone = new HashMap<String, String>() {
{
put("2", "abc");
put("3", "def");
put("4", "ghi");
put("5", "jkl");
put("6", "mno");
put("7", "pqrs");
put("8", "tuv");
put("9", "wxyz");
}
};
List<String> strList = new ArrayList<>();
public void recursion(String combination, String next_digits) {
if (next_digits.length() == 0) {
strList.add(combination);
} else {
String digit = next_digits.substring(0, 1);
String letters = phone.get(digit);
for (int i = 0; i < letters.length(); i++) {
String letter = phone.get(digit).substring(i, i + 1);
recursion(combination + letter, next_digits.substring(1));
}
}
}
public List<String> letterCombinations(String digits) {
if (digits != null && digits.length() != 0)
recursion("", digits);
return strList;
}
}