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WordPattern.java
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72 lines (47 loc) · 1.56 KB
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package other;
import java.util.HashMap;
import java.util.Map;
/**
* @Author: Wenhang Chen
* @Description:给定一种规律 pattern 和一个字符串 str ,判断 str 是否遵循相同的规律。
* <p>
* 这里的 遵循 指完全匹配,例如, pattern 里的每个字母和字符串 str 中的每个非空单词之间存在着双向连接的对应规律。
* <p>
* 示例1:
* <p>
* 输入: pattern = "abba", str = "dog cat cat dog"
* 输出: true
* 示例 2:
* <p>
* 输入:pattern = "abba", str = "dog cat cat fish"
* 输出: false
* 示例 3:
* <p>
* 输入: pattern = "aaaa", str = "dog cat cat dog"
* 输出: false
* 示例 4:
* <p>
* 输入: pattern = "abba", str = "dog dog dog dog"
* 输出: false
* 说明:
* 你可以假设 pattern 只包含小写字母, str 包含了由单个空格分隔的小写字母。
* @Date: Created in 10:29 2/19/2020
* @Modified by:
*/
public class WordPattern {
public boolean wordPattern(String pattern, String str) {
String[] words = str.split(" ");
Map<Character, String> map = new HashMap<>();
if (pattern.length() != words.length) return false;
for (int i = 0; i < pattern.length(); i++) {
if (!map.containsKey(pattern.charAt(i))) {
if (map.containsValue(words[i])) return false;
map.put(pattern.charAt(i), words[i]);
} else {
if (!map.get(pattern.charAt(i)).equals(words[i]))
return false;
}
}
return true;
}
}