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BinaryTreeLevelOrderTraversal.java
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74 lines (65 loc) · 1.73 KB
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package binary_tree;
import java.util.*;
/**
* @Author: Wenhang Chen
* @Description:给定一个二叉树,返回其按层次遍历的节点值。 (即逐层地,从左到右访问所有节点)。
* <p>
* 例如:
* 给定二叉树: [3,9,20,null,null,15,7],
* <p>
* 3
* / \
* 9 20
* / \
* 15 7
* 返回其层次遍历结果:
* <p>
* [
* [3],
* [9,20],
* [15,7]
* ]
* @Date: Created in 20:19 1/24/2020
* @Modified by:
*/
public class BinaryTreeLevelOrderTraversal {
public class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int x) {
val = x;
}
}
public List<List<Integer>> levelOrder(TreeNode root) {
List<List<Integer>> res = new ArrayList<>();
Queue<TreeNode> queue = new LinkedList<>();
if (root != null) queue.add(root);
int curCount = 1;
int nextCount = 0;
List<Integer> valueList = new ArrayList<>();
while (!queue.isEmpty()) {
curCount--;
TreeNode node = queue.poll();
if (node.left != null) {
queue.add(node.left);
nextCount++;
}
if (node.right != null) {
queue.add(node.right);
nextCount++;
}
valueList.add(node.val);
if (curCount == 0) {
// 直接add会报错,因为valueList自始至终指向同一个对象
// res.add(valueList);
// 集合对象复制这边有坑
res.add(new ArrayList(valueList));
valueList.clear();
curCount = nextCount;
nextCount = 0;
}
}
return res;
}
}