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10081.cpp
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105 lines (96 loc) · 3.2 KB
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/****** BISMILLAHIR RAHMANIR RAHIM ********\
/*********************************************************************\
# |--\ /--| | | | ----- /-------------\ #
# | \ / | | | | / | | #
# | \ / | | | | / | | #
# | | | | |/ | | #
# | | | | |\ | | #
# | | | | | \ | | #
# | | \ / | \ | | #
# --- --- \______ / | ----- ----- #
# #
# #
# #
# codeforces = Mukit09 #
# topcoder = mukitmkbs25 #
# codechef = mukit_mkbs #
# uva = mkbs_cse09 #
# spoj = mkbs_cse09 #
# CSE, CUET #
# facebook : https://www.facebook.com/hesitated.mkbs?ref=tn_tnmn #
# #
# #
\*********************************************************************/
#include<stdio.h>
#include<iostream>
#include<math.h>
#include<string.h>
#include<string>
#include<stdlib.h>
#include<map>
#include<vector>
#include<queue>
#include<stack>
#include<algorithm>
#include<set>
using namespace std;
// Define Some Variables
#define eps 1e-14
#define si 100010
#define pi acos(-1.0)
#define inf (1<<30)-1
#define mod 1000000000 //10^9
//Define Some Functions
#define even(a) ((a)%2==0)
#define odd(a) ((a)%2==1)
#define max(a,b) (a>b ?a:b)
#define min(a,b) (a<b ?a:b)
#define pb push_back
#define mpair make_pair
#define sqr(a)((a)*(a))
#define area(x1,y1,x2,y2,x3,y3) (x1*(y2-y3)+x2*(y3-y1)+x3*(y1-y2)) //Area of a triangle
#define dist(x1,y1,x2,y2) (sqr(x1-x2)+sqr(y1-y2)) //Distance between two points
#define mem(a,v) memset(a,v,sizeof(a))
inline bool compare( double a, double b ) { return fabs( a-b ) < eps ; }
#define fr(i,a,b) for(i=a;i<=b;i++)
#define rep(i,a,b) for(i=a;i<b;i++)
#define rev(i,a,b) for(i=a;i>=b;i--)
typedef long long i64;
int dx[]={0,0,1,-1};
int dy[]={1,-1,0,0};
int l,n,cs=1,cnt,sm,fg,k;
double dp[11][101];
double rec(int dig,int len)
{
if(len==n)
return 1.0;
double &ret=dp[dig][len];
if(ret!=-1)
return ret;
ret=0.0;
ret+=rec(dig,len+1);
if(dig<k)
ret+=rec(dig+1,len+1);
if(dig>0)
ret+=rec(dig-1,len+1);
return ret;
}
int main()
{
// freopen("input.txt", "r", stdin);
// freopen("output.txt", "w", stdout);
int i,j;
while(~scanf("%d%d",&k,&n))
{
double ans=0;
rep(i,0,k+1)
{
rep(j,0,n)
dp[i][j]=-1.0;
}
fr(i,0,k)
ans+=rec(i,1);
printf("%.5lf\n",(ans*100.0)/pow(k+1,n));
}
return 0;
}